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Find second largest number in a list


#Python Program to find Second Largest number in List with Sort
#/usr/bin/python3

n = int(input())
if ( n >= 2 and n <= 10):
lst = set(list(map(int,input().split()))) #Set's will avoid duplicated
new_lst = list(lst)
new_lst.sort()
print(new_lst[-2])


# Python Program to find Second Largest number in List Without Sort
#/usr/bin/python3

n = int(input())
a = list(map(int,input().split()))
f_num = a[0]
s_num = 0;

for i in range(1,n):
 if(f_num > a[i] and a[i] > s_num) :
  s_num = a[i]
 if(a[i] > f_num):
  s_num = f_num;
  f_num = a[i]
print("Second Large number is :-",s_num)


Input - 5
5 2 10 1 2

Output -
Second Large number is :- 5


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